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4.9x^2+3.2x-10=0
a = 4.9; b = 3.2; c = -10;
Δ = b2-4ac
Δ = 3.22-4·4.9·(-10)
Δ = 206.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{206.24}}{2*4.9}=\frac{-3.2-\sqrt{206.24}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{206.24}}{2*4.9}=\frac{-3.2+\sqrt{206.24}}{9.8} $
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